Java语言程序设计答案王振飞_JAVA语言程序设计（基础篇） 第十版——第七章 一维数组 （参考答案）…

(7.2~7.5节)+(7.6~7.8节)+7.9节+(7.10~7.12节)

我只做到了21题，有点乏了，未完待续………(以后更新)

(7.2~7.5节)

*7.1(指定等级)

import java.util.Scanner;

public class S1 {

public static void main(String[] args) {

Scanner input=new Scanner(System.in);

System.out.print(“Enter the number of students: “);

int numbers=input.nextInt();

System.out.print(“Enter “+numbers+” scores: “);

int[] scores=new int[numbers];

for(int i=0; i

scores[i]=input.nextInt();

}

int best=scores[0];

for(int i=1; i

if(best

best=scores[i];

}

char[] ch= {‘A’,’B’,’C’,’D’,’E’,’F’};

for(int i=0; i

if(scores[i]>=best-10)

System.out.println(“Student “+i+” score is “+scores[i]+” and grade is “+ch[0]);

else if(scores[i]>=best-20)

System.out.println(“Student “+i+” score is “+scores[i]+” and grade is “+ch[1]);

else if(scores[i]>=best-30)

System.out.println(“Student “+i+” score is “+scores[i]+” and grade is “+ch[2]);

else if(scores[i]>=best-40)

System.out.println(“Student “+i+” score is “+scores[i]+” and grade is “+ch[3]);

else

System.out.println(“Student “+i+” score is “+scores[i]+” and grade is “+ch[4]);

}

input.close();

}

}

7.2(倒置输入的数)

import java.util.Scanner;

public class S2 {

public static void main(String[] args) {

Scanner input=new Scanner(System.in);

System.out.print(“请输入10个整数: “);

int[] numbers=new int[10];

for(int i=0; i

numbers[i]=input.nextInt();

}

for(int i=numbers.length-1; i>=0; i–) {

System.out.print(” “+numbers[i]);

}

input.close();

}

}

**7.3(计算数字出现的次数)

参考大神博客会有不同解法：

(https://blog.csdn.net/weixin_46215617/article/details/105097958?depth_1-utm_source=distribute.pc_relevant.none-task&utm_source=distribute.pc_relevant.none-task)

(https://blog.csdn.net/LEE_FIGHTING_JINGYU/article/details/80009407?depth_1-utm_source=distribute.pc_relevant.none-task&utm_source=distribute.pc_relevant.none-task)

在这里我用count[1]存储数字1的次数，用count[2]存储数字2的次数,……,以此类推。

import java.util.Scanner;

public class S3 {

public static void main(String[] args) {

Scanner input=new Scanner(System.in);

System.out.print(“Enter tne integers between 1 and 100: “);

int number=input.nextInt();

int[] counts=new int[102];

int i=1;

while(number!=0) {

if(number>=1 && number<=100) {

counts[number]++;

}

number=input.nextInt();

}

for(int j=1; j<=100; j++) {

if(counts[j]>0) {

System.out.println(j+” occurs “+counts[j]+(counts[j]>1 ? ” times.” :” time.”));

}

}

input.close();

}

}

7.4(分析成绩)