已知二维数组A[1:4,1:6]_给定长度为2n的数组,你的任务是「建议收藏」

一维数组实验题：大奖赛现场统分。已知某大奖赛有n个选手参赛，m（m>2）个评委为参赛选手评分（最高10分，最低0分）。统分规则为：在每个选手的m个得分中，去掉一个最高分和一个最低分后，取平均分作为该选手的最后得分。要求编程实现：
（1）根据n个选手的最后得分，从高到低输出选手的得分名次表，以确定获奖名单；
（2）根据各选手的最后得分与各评委给该选手所评分数的差距，对每个评委评分的准确性和评分水准给出一个定量的评价，每位评委的评分方法：(10 -(评委对选手x的评分 – x的得分)^2 的累加和)，从高到低输出各评委得分的名次表。
输入提示：
printf(“How many Athletes?”);
scanf(“%d”, &n); /* 输入选手人数 /
printf(“How many judges?”);
scanf(“%d”, &m); / 输入评委人数 */

printf("Order of Athletes:\n");          /* 选手得分排序 */                       
printf("Order of judges:\n");            /* 评委得分排序 */

/* 函数功能：统计参赛选手的得分 */
void CountAthleteScore(int sh[], float sf[], int n, float f[], int m)
printf(“\nAthlete %d is playing.”, i);
printf(“\nPlease enter his number code:”);
scanf(“%d”, &sh[i]);

for (j = 1; j <= m; j++) /* 第j个评委 */
{

printf(“Judge %d gives score:”, j);

    printf("Delete a maximum score:%.1f\n", max);
    printf("Delete a minimum score:%.1f\n", min);    /*去掉一个最高分和最低分*/

/* 函数功能：对分数从高到低排序 */
void Sort(int h[], float f[], int n)

/* 函数功能：打印名次表 */
void Print(int h[], float f[], int n)
printf(“order\tfinal score\tnumber code\n”);
printf(“%5d\t%11.3f\t%6d\n”, i, f[i], h[i]);

/* 函数功能：统计评委的得分 */
void CountJudgeScore(int ph[], float pf[], int m, float sf[], float f[], int n)

程序运行示例如下：
How many Athletes?5
How many judges?5
Scores of Athletes:
Athlete 1 is playing.
Please enter his number code:11
Judge 1 gives score:9.5
Judge 2 gives score:9.6
Judge 3 gives score:9.7
Judge 4 gives score:9.4
Judge 5 gives score:9.0
Delete a maximum score:9.7
Delete a minimum score:9.0
The final score of Athlete 11 is 9.500

Athlete 2 is playing.
Please enter his number code:12
Judge 1 gives score:9.0
Judge 2 gives score:9.2
Judge 3 gives score:9.1
Judge 4 gives score:9.3
Judge 5 gives score:8.9
Delete a maximum score:9.3
Delete a minimum score:8.9
The final score of Athlete 12 is 9.100

Athlete 3 is playing.
Please enter his number code:13
Judge 1 gives score:9.6
Judge 2 gives score:9.7
Judge 3 gives score:9.5
Judge 4 gives score:9.8
Judge 5 gives score:9.4
Delete a maximum score:9.8
Delete a minimum score:9.4
The final score of Athlete 13 is 9.600

Athlete 4 is playing.
Please enter his number code:14
Judge 1 gives score:8.9
Judge 2 gives score:8.8
Judge 3 gives score:8.7
Judge 4 gives score:9.0
Judge 5 gives score:8.6
Delete a maximum score:9.0
Delete a minimum score:8.6
The final score of Athlete 14 is 8.800

Athlete 5 is playing.
Please enter his number code:15
Judge 1 gives score:9.0
Judge 2 gives score:9.1
Judge 3 gives score:8.8
Judge 4 gives score:8.9
Judge 5 gives score:9.2
Delete a maximum score:9.2
Delete a minimum score:8.8
The final score of Athlete 15 is 9.000
Order of Athletes:
order final score number code
1 9.600 13
2 9.500 11
3 9.100 12
4 9.000 15
5 8.800 14
Order of judges:
order final score number code
1 9.980 1
2 9.960 2
3 9.900 3
4 9.860 4
5 9.590 5
Over!Thank you!

#include <stdio.h>
#include <math.h>

void  CountAthleteScore(int sh[], float sf[], int n, float f[][10], int m); /* 函数功能：统计参赛选手的得分 */
void Sort(int h[], float f[], int n); /* 函数功能：对分数从高到低排序 */
void Print(int h[], float f[], int n); /* 函数功能：打印名次表 */
void CountJudgeScore(int ph[], float pf[], int m, float sf[], float f[][10],  int n); /* 函数功能：统计评委的得分 */

int main()
{ 
   
    int n,m,sh[10],ph[10];                          //sh[]选手编号,ph[]评委编号
    float sf[10],f[10][10],pf[10];                            //f[]每个评委给选手打分，sf[]每个选手最终得分,pf[]评委得分
    printf("How many Athletes?");
    scanf("%d", &n);                                /* 输入选手人数 */
    printf("How many judges?");
    scanf("%d", &m);                              /* 输入评委人数 */
    printf("Scores of Athletes:\n");
    CountAthleteScore(sh,sf,n,f,m);
    CountJudgeScore(ph,pf,m,sf,f,n);
    Sort(sh,sf,n);                                 //选手成绩排序
    printf("Order of Athletes:\n");          /* 选手得分排序 */
    Print(sh,sf,n);                                //选手排名打印
    printf("Order of judges:\n");            /* 评委得分排序 */
    Sort(ph,pf,m);
    Print(ph,pf,m);
    printf("Over!Thank you!");
    return 0;
}

void  CountAthleteScore(int sh[], float sf[], int n, float f[][10], int m)
{ 
   
    int i,j,k,g,t,w,e;
    float s,max,min;
    for(i=0;i<n;i++)
    { 
   
        printf("\nAthlete %d is playing.", i+1);
        printf("\nPlease enter his number code:");
        scanf("%d", &sh[i]);
        for (j = 0; j < m; j++)              //录入成绩
        { 
   
            printf("Judge %d gives score:", j+1);
            scanf("%f",&f[i][j]);
            getchar();
        }
        max=f[i][0];
        w=0;
        for(g=1;g<m;g++)
        { 
   
            if(max<f[i][g])
            { 
   
                max=f[i][g];
                w=g;//记录最高分标号
            }
        }
        min=f[i][0];
        e=0;
        for(t=1;t<m;t++)
        { 
   
            if(min>f[i][t])
            { 
   
                min=f[i][t];
                e=t;//记录最低分标号
            }
        }
        printf("Delete a maximum score:%.1f\n", max);
        printf("Delete a minimum score:%.1f\n", min);    /*去掉一个最高分和最低分*/
        s=0;
        for(k=0;k<m;k++)          //计算最终得分
        { 
   
            if(k!=w&&k!=e)
                s+=f[i][k];
        }
        sf[i]=s/(m-2);
        printf("The final score of Athlete %d is %.3f\n",sh[i],sf[i]);
    }
}

void Sort(int h[], float f[], int n)
{ 
   
    int i,j;
    float t;
    for(i=0;i<n-1;i++)
    { 
   
        for(j=i+1;j<n;j++)
        { 
   
            if(f[i]<f[j])
            { 
   
                t=f[i];
                f[i]=f[j];      //交换成绩
                f[j]=t;
                t=h[i];
                h[i]=h[j];      //交换编号
                h[j]=t;
            }
        }
    }
}

void Print(int h[], float f[], int n)
{ 
   
    int i;
    printf("order\tfinal score\tnumber code\n");
    for(i=0;i<n;i++)
    { 
   
        printf("%5d\t%11.3f\t%6d\n", i+1, f[i], h[i]);
    }
}

void CountJudgeScore(int ph[], float pf[], int m, float sf[], float f[][10],  int n)
{ 
   
    int i,j;
    float s,t;
    for(i=0;i<m;i++)
    { 
   
        s=0;
        for(j=0;j<n;j++)
        { 
   
            t=(f[j][i]-sf[j])*(f[j][i]-sf[j]);
            s+=t;
        }
        pf[i]=10-s;
        ph[i]=i+1;
    }
}

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