问题:数组对象去重
方法一:es5冒泡排序法,去重arr(较好用)
var arr = [{name: 'a',id: 1}, {name: 'a',id: 2}, {name: 'b',id: 3}, {name: 'c',id: 4},
{name: 'c',id: 6}, {name: 'b',id: 6}, {name: 'd',id: 7}];
function deWeight() {
for (var i = 0; i < arr.length - 1; i++) {
for (var j = i + 1; j < arr.length; j++) {
if (arr[i].name == arr[j].name) {
arr.splice(j, 1);
//因为数组长度减小1,所以直接 j++ 会漏掉一个元素,所以要 j--
j--;
}
}
}
return arr;
}
var newArr = deWeight();
console.log('%c%s', 'color:red;', '方法一:es5,newArr', newArr);
方法二:es5新建数据双重循环,去重arr2
var arr2 = [{name: 'a',id: 1}, {name: 'a',id: 2}, {name: 'b',id: 3}, {name: 'c',id: 4},
{name: 'c',id: 6}, {name: 'b',id: 6}, {name: 'd',id: 7}];
var temp = [];
function deWeightTwo() {
arr2.forEach(function(a) {
var check = temp.every(function(b) {
return a.name !== b.name;
})
check ? temp.push(a) : ''
})
return temp;
}
var newArr2 = deWeightTwo();
console.log('%c%s', 'color:red;', '方法二:es5,newArr2', newArr2);
方法三:es6的Map(),去重arr3
var arr3 = [{name: 'a',id: 1}, {name: 'a',id: 2}, {name: 'b',id: 3}, {name: 'c',id: 4},
{name: 'c',id: 6}, {name: 'b',id: 6}, {name: 'd',id: 7}];
let deWeightThree = () => {
let map = new Map();
for (let item of arr3) {
if (!map.has(item.name)) {
map.set(item.name, item);
}
}
return [...map.values()];
}
let newArr3 = deWeightThree();
console.log('%c%s', 'color:red;', '方法三:es6,newArr3', newArr3);
方法四:es5,对象法去重arr4
var arr4 = [{name: 'a',id: 1}, {name: 'a',id: 2}, {name: 'b',id: 3}, {name: 'c',id: 4},
{name: 'c',id: 6}, {name: 'b',id: 6}, {name: 'd',id: 7}];
// array.reduce(function(total, currentValue, currentIndex, arr), initialValue)
// (function(必选初始值或计算结束返回值, 必选当前元素, 可选索引, 可选原数组),可选函数初始值)
var obj = {};
function deWeightFour() {
arr4 = arr4.reduce(function(a, b) {
obj[b.name] ? '' : obj[b.name] = true && a.push(b);
return a;
}, [])
return arr4;
}
var newArr4 = deWeightFour();
console.log('%c%s', 'color:red;', '方法四:es5,newArr4', newArr4);
今天的文章js数组中对象去重(真的好实用!!!!)_js数组对象筛选出重复分享到此就结束了,感谢您的阅读。
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